F(x)=3x^2-12x+16

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Solution for F(x)=3x^2-12x+16 equation: 



(F)=3F^2-12F+16

We move all terms to the left:

(F)-(3F^2-12F+16)=0

We get rid of parentheses

-3F^2+F+12F-16=0

We add all the numbers together, and all the variables

-3F^2+13F-16=0

a = -3; b = 13; c = -16;
Δ = b2-4ac
Δ = 132-4·(-3)·(-16)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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